SOLUTION Here only tan x occurs, so we use tan 2x sec 2x 1 to rewrite a tan 2x factor in terms of sec 2x y tan x dx y tan x tan x dx 3 2 y tan x sec 2x 1 dx y tan x sec 2x dx y tan x dx tan 2x 2 ln sec x C In the first integral we mentally substituted u tan x so that du sec 2x dx2 The answer is this but the coefficient is 1 4 Why? · If \(k\) is even and \(j\) is odd, then use \(\tan^2x=\sec^2x−1\) to express \(\tan^kx\) in terms of \(\sec x\) Use integration by parts to integrate odd powers of \(\sec x\) Example \(\PageIndex{8}\) Integrating \(∫\tan^kx\sec^jx\,dx\) when \(j\) is Even
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Tan^2x secx integral
Tan^2x secx integral-Evaluate integral of 1/(sec(x)^2) with respect to x Simplify Tap for more steps Rewrite as Rewrite as Rewrite in terms of sines and cosines Multiply by the reciprocal of the fraction to divide by Multiply by Use the halfangle formula to rewrite asSubsection 1 Integrating \(\int \tan^m x\sec^n x\dee{x}\) The strategy for dealing with these integrals is similar to the strategy that we used to evaluate integrals of the form \(\int \sin^m x\cos^n x\dee{x}\) and again depends on the parity of the exponents \(n\) and \(m\text{}\)


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The Integral Calculator supports definite and indefinite integrals (antiderivatives) as well as integrating functions with many variables You can also check your answers! · Using properties of definite integrals, evaluate the following∫(0>π) (x tanx)/(secxtanx) dx · Integral of u^2 is NOT (u^3)/3 c Rather, integral of (u^2)du = (u^3)/3 c In (tan^2)x your 1st mistake is not writing dx Note that dx is NOT always du!!!!!
Question Find the indefinite integral (Use C for the constant of integration) I see sec 2x tan 2x dx This problem has been solved!Integrate sec^22x To integrate sec^22x, also written as ∫sec 2 2x dx, sec squared 2x, (sec2x)^2, and sec^2 (2x), we start with a u substitution Let u = 2x This is a simple u substitution Therefore du/dx = 2 This is a simple differentiation step We rearrange the previous expression for dxWe can simplify the implementation of the integral with the help of substitution, wherein we allow u= sec2x u = sec 2 x This substitution entails the change in the differential variable and the
The definite integral of from to , denoted , is defined to be the signed area between and the axis, from to Both types of integrals are tied together by the fundamental theorem of calculus This states that if is continuous on and is its continuous indefinite integral, then This means Sometimes an approximation to a definite integral is(Use C for the constant of integration) I see sec 2x tan 2x dx ;\\int \tan^{2}x\sec{x} \, dx\ > <



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Derivatives Derivative Applications Limits Integrals Integral Applications Integral Approximation Series ODE Multivariable Calculus Laplace Transform Taylor/Maclaurin Series Fourier Series Functions Line Equations Functions Arithmetic & Comp Conic Sections TransformationSolution for Evaluate the integral S tan (2x) sec°(2x) dx Social Science AnthropologySolution for 11 Evaluate the integral tan 2x dx A In sec 21 C sec² 2x C С In cos 24 C D 2 sec 2x C В



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· Write tan 3 (2x) as tan 2 (2x)tan(2x) = sec 2 (2x)1tan(2x) Now the function is Integral sec 2 (2x)1 tan(2x) sec(2x)dx Put sec(2x) = u sec(2x)tan(2x)dxUse \(\tan^2x=\sec^2x1~(=u^21)\) to replace the leftover tangents \(m\) is even or \(n\) is odd Use either \(1\) or \(2\) (both will work) The power of secant is odd and the power of tangent is even No guideline The integrals \(\ds\int\sec x\,dx\) and \(\ds\int\sec^3 x\,dx\) can usually be looked up, or recalled from memory Example 223Expert Answer Previous question Next question



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See the answer How do you solve this integral of 3 sec(2x1)tan(2x1)?Question How Do You Solve This Integral Of 3 Sec(2x1)tan(2x1)?I = sec 2xdx Multiplying in Nr and Dr by (sec 2xtan 2x ) I = {sec 2x(sec 2x tan 2x)/(sec 2x tan 2x)}dx Let (sec 2x tan 2x) = p then2(sec 2xtan 2x sec^2 2x)dx = dp or, sec 2x(tan 2x sec 2x)dx = 1/2dp I = (1/2)(1/p)dp I = 1/2 log p C I = (1/2) log sec 2x tan 2



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Integrate 2sec^2x tanx To integrate 2sec^2x tanx, also written as ∫2sec 2 x tanx dx, 2 sec squared x tan x, and 2 (sec x)^2 tanx, we start by recognising that the differential of one half is within the other half of the same expressionDifferentiate c and d, use the product rule to find v Then just use the product rule on u and v 0 · Here, notice that sec^2x is already in the integral, and all that remains is tan^2x That is, we have tanx in squared form accompanied by its derivative, sec^2x This integral is ripe for substitution!


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